Finding Min/Max of a function for HP-67

[Dieter]

(05-22-2016 10:35 PM)PedroLeiva Wrote:  The point is that in the original post of this program was no explanation about how to determine Max. or min. (or I did not realize).

The program implements a simple Newton iteration to find the zeroes of the derivative f'(x). In a minimum or maximum f'(x) must be zero, and this is what the program finds. It evaluates x_new = x – f'(x) / f"(x).

(05-22-2016 10:35 PM)PedroLeiva Wrote:  From the two options for cheking, I prefer: x<>y (+1, -1), for Max. & min., respectively.

This is what the proposed code does. It returns +1 for a maximum and –1 for a minimum.

Dieter