For which models was 2^3>8?
04-04-2017, 06:10 PM (This post was last modified: 04-04-2017 06:11 PM by pier4r.)
Post: #8
 pier4r Senior Member Posts: 2,019 Joined: Nov 2014
RE: For which models was 2^3>8?
Thanks Dieter! Yes I choose the square root of 169 because as far as I know it involves a bit of calculations and it could lead to errors.

For the $$e^{x \cdot ln(y)}$$ I did not think they would use that unless rational numbers were used as input. For special cases, like 2, I also thought about shortcuts ( shifting bits ). Well, once again, today I learned.

Wikis are great, Contribute :)
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 Messages In This Thread For which models was 2^3>8? - Joe Horn - 04-04-2017, 05:03 AM RE: For which models was 2^3>8? - james summers - 04-04-2017, 06:26 AM RE: For which models was 2^3>8? - Joe Horn - 04-04-2017, 12:17 PM RE: For which models was 2^3>8? - james summers - 04-04-2017, 01:05 PM RE: For which models was 2^3>8? - Dave Britten - 04-04-2017, 03:28 PM RE: For which models was 2^3>8? - pier4r - 04-04-2017, 05:20 PM RE: For which models was 2^3>8? - Dieter - 04-04-2017, 05:51 PM RE: For which models was 2^3>8? - Thomas Okken - 04-04-2017, 10:26 PM RE: For which models was 2^3>8? - Dave Britten - 04-05-2017, 11:34 AM RE: For which models was 2^3>8? - pier4r - 04-04-2017 06:10 PM RE: For which models was 2^3>8? - bshoring - 04-04-2017, 06:16 PM RE: For which models was 2^3>8? - teenix - 04-05-2017, 07:50 AM RE: For which models was 2^3>8? - bshoring - 04-05-2017, 06:08 PM RE: For which models was 2^3>8? - james summers - 04-04-2017, 06:45 PM RE: For which models was 2^3>8? - Dieter - 04-04-2017, 07:18 PM RE: For which models was 2^3>8? - james summers - 04-04-2017, 07:42 PM RE: For which models was 2^3>8? - Dieter - 04-04-2017, 07:53 PM RE: For which models was 2^3>8? - bshoring - 04-04-2017, 10:14 PM RE: For which models was 2^3>8? - Andres - 06-23-2020, 04:39 AM

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