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Little explorations with HP calculators (no Prime)
03-27-2017, 03:44 PM (This post was last modified: 03-27-2017 03:44 PM by Thomas Okken.)
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RE: Little explorations with the HP calculators
(03-27-2017 02:27 PM)pier4r Wrote:  
(03-27-2017 12:54 PM)Thomas Okken Wrote:  Consider a unit circle jammed into the corner of the first quadrant (so its center is at (1, 1)). Now consider a radius of that circle sweeping the angles from 0 to pi/2. The point P on the circle where that radius intersects it is at (1 + cos(phi), 1 + sin(phi)).

I'm a bit blocked.

http://i.imgur.com/IW4QIeU.jpg

Would be possible to add a quick sketch?

OK; I attached a sketch to my previous post.
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RE: Little explorations with the HP calculators - Thomas Okken - 03-27-2017 03:44 PM



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