Little explorations with HP calculators (no Prime)

03272017, 02:27 PM
(This post was last modified: 03272017 02:28 PM by pier4r.)
Post: #29




RE: Little explorations with the HP calculators
(03272017 12:54 PM)Thomas Okken Wrote: Consider a unit circle jammed into the corner of the first quadrant (so its center is at (1, 1)). Now consider a radius of that circle sweeping the angles from 0 to pi/2. The point P on the circle where that radius intersects it is at (1 + cos(phi), 1 + sin(phi)). I'm a bit blocked. http://i.imgur.com/IW4QIeU.jpg Would be possible to add a quick sketch? Wikis are great, Contribute :) 

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