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Free42 with IEEE 754-2008 decimal floating-point -- interested in a sneak preview?
03-18-2014, 07:57 AM
Post: #87
RE: Free42 with IEEE 754-2008 decimal floating-point - interested in a sneak preview?
(03-18-2014 07:16 AM)Werner Wrote:  
(03-17-2014 01:29 PM)Thomas Okken Wrote:    10n ≤ x < 10n+1 → n ≤ LOG(x) < n+1
This is not possible.
On a real 42S, LOG(9.99999999999) = 1, exactly. Meaning it is the closest number to the exact result. The same holds for any precision. On Free42 Decimal-34, LOG(1e34-1) is 34 and LOG(1e33-1) is 33, exactly, and that's what the result should be.

I tend to agree with Werner, and the condition above is not needed. Strictly speaking, all we need is that 10^x is exact for x an integer, and it will be nice that LOG(x) is an integer for x exactly a power of ten.

J-F
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RE: Free42 with IEEE 754-2008 decimal floating-point - interested in a sneak preview? - J-F Garnier - 03-18-2014 07:57 AM



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