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(sqrt(-2))^2
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10-05-2016, 03:04 PM
Post: #3
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RE: (sqrt(-2))^2
First you should not need brackets in this case.
Second if you look at the third picture the input line is equal to the left term (input) in the upper line, so both should give the same result. |
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| Messages In This Thread |
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(sqrt(-2))^2 - retoa - 10-05-2016, 02:33 PM
RE: (sqrt(-2))^2 - toml_12953 - 10-05-2016, 03:01 PM
RE: (sqrt(-2))^2 - retoa - 10-05-2016 03:04 PM
RE: (sqrt(-2))^2 - parisse - 10-05-2016, 07:13 PM
RE: (sqrt(-2))^2 - retoa - 10-05-2016, 09:24 PM
RE: (sqrt(-2))^2 - Tim Wessman - 10-05-2016, 10:37 PM
RE: (sqrt(-2))^2 - parisse - 10-06-2016, 05:10 AM
RE: (sqrt(-2))^2 - retoa - 10-06-2016, 06:47 AM
RE: (sqrt(-2))^2 - Tim Wessman - 10-06-2016, 02:12 PM
RE: (sqrt(-2))^2 - parisse - 10-06-2016, 06:05 PM
RE: (sqrt(-2))^2 - John P - 10-06-2016, 07:26 PM
RE: (sqrt(-2))^2 - compsystems - 10-06-2016, 07:58 PM
RE: (sqrt(-2))^2 - compsystems - 10-06-2016, 04:01 PM
RE: (sqrt(-2))^2 - parisse - 10-06-2016, 08:19 PM
RE: (sqrt(-2))^2 - compsystems - 10-06-2016, 08:36 PM
RE: (sqrt(-2))^2 - parisse - 10-07-2016, 06:27 AM
RE: (sqrt(-2))^2 - compsystems - 10-08-2016, 03:38 AM
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