Evaluating Undefined expressions?

[Han]

(11-06-2015 08:38 AM)retoa Wrote:  Does it not depend on from where you approach zero?

If you approach zero coming from +1 you get for 5/0 a positive value which then tend to infinity.
If you approach zero coming from -1 you get for 5/0 a negative value which then tend to a negative infinity, so 2+(-infinity)=-infinity < 1

I think you missed the absolute value signs.