Brain Teaser - Area enclosed by a parabola and a line

[Gerson W. Barbosa]

(09-15-2015 05:00 PM)fhub Wrote:  

(09-15-2015 04:18 PM)Gerson W. Barbosa Wrote:  I think I can blame it on my Simpson 3/8 integrator in Pascal (too many iterations required!). Your result is indeed a minimum, as checked in W|A:

I don't think that you can solve any intermediate steps approximately, at least I have done the complete calculation with exact terms, only the last equation A'(u)=0 has to be done approximately of course. And these intermediate expressions (left intersection point, the formula for A(u) after the definite integration) are really HUGE!

For all this I've used my good old Derive 4.11 (the DOS version because I'm familiar with it since more than 20 years)!

Franz

Wolfram Alpha would not allow me to copy and past the very expression for the left integration limit (unless of course I subscribed to their service), so I didn't even try. I am not familiar with the Prime, but I think it can handle that, can't it?

Gerson.