Quiz: calculating a definite integral
01-07-2014, 06:12 PM
Post: #45
 Bunuel66 On Vacation Posts: 29 Joined: Jan 2014
RE: Quiz: calculating a definite integral
(01-06-2014 10:28 AM)Thomas Klemm Wrote:
(01-03-2014 09:04 PM)Bunuel66 Wrote:  Don't get the point, $$\exp(-\infty)$$=0.

The domain of $$\exp(x)$$ is $$\mathbb{R}$$, but $$-\infty \notin \mathbb{R}$$. Thus you can not just plug $$-\infty$$ into the Taylor-series of this function and expect everything works. You can calculate $$\lim_{x\to\infty}\exp(x)$$ but that's not the same as $$\exp(-\infty)$$. This expression is just not defined.

HTH
Thomas

Could have been rewriten as a limit to be more rigorous...;-) That said the serie gives the same value than the function also for x<0. Doesn't seems to be the point. And as you mention this is not a Taylor serie strictly speaking.

Regards.
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