# Line slope calculator 9x+5y=59

**Straight line given by points A[1; 10] and B[6; 1]**

## Calculation:

**Slope-intercept form of line:**y = -1.8x+11.8

**Canonical form of the line equation:**9x+5y-59 = 0

**Parametric form of the line equation:**

x = 5t+1

y = -9t+10 ; t ∈ R

**Slope:**m = -1.8

**Slope angle of line: φ =**-60°56'43″ = -1.0637 rad

**X intercept:**x

_{0}= 6.5556

**Y intercept:**y

_{0}= q = 11.8

**Distance line from the origin:**d

_{0}= 5.7306

**The length of the segment AB: |AB| =**10.2956

**Vector: AB =**(5; -9)

**Normal vector: n =**(9; 5)

**Midpoint of the segment AB: M =**[3.5; 5.5]

**Perpendicular Bisector equation:**5x-9y+32 = 0

**Vector OA = (1; 10) ; |OA| = 10.0499**

**Vector OB = (6; 1) ; |OB| = 6.0828**

**Scalar product OA .OB = 16**

**Angle ∠ AOB = 74°49'37″ = 1.306 rad**