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(28/48/50) Lambert W Function
01-30-2024, 02:52 PM
Post: #40
RE: (28/48/50) Lambert W Function
I tried and changed the code fo my function FNL relative to ln(1+x)-x

FNL=
«
WHILE x .4 >=
REPEAT 'x/(sqrt(1+x)+1)' ->NUM 'x' STO x FNL 2 * x SQ - 'fnl' STO
END 'x/(x+2)' ->NUM 'X2' STO X2 DUP * 'X4' STO 'X4*(5005-X4*(5082-X4*969))/(15015-X4*(24255-X4*(11025-X4*1225)))' ->NUM 'X4' STO 'X2*(X4+X4-x)' ->NUM 'fnl' STO
»

But, for initial x=4, I get a final fnl = -4.77474540488E-2 that is incorrect, of course.
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Messages In This Thread
(28/48/50) Lambert W Function - John Keith - 03-20-2023, 08:43 PM
RE: (28/48/50) Lambert W Function - Gil - 01-29-2024, 11:04 AM
RE: (28/48/50) Lambert W Function - Gil - 01-29-2024, 02:47 PM
RE: (28/48/50) Lambert W Function - Gil - 01-29-2024, 06:46 PM
RE: (28/48/50) Lambert W Function - Gil - 01-29-2024, 09:50 PM
RE: (28/48/50) Lambert W Function - Gil - 01-30-2024, 12:33 AM
RE: (28/48/50) Lambert W Function - Gil - 01-30-2024, 12:04 PM
RE: (28/48/50) Lambert W Function - Gil - 01-30-2024 02:52 PM
RE: (28/48/50) Lambert W Function - Gil - 01-31-2024, 07:10 PM



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