How to use graphic.draw_filled_polygon?

[Guenter Schink]

(11-29-2021 02:22 PM)toml_12953 Wrote:  

(11-29-2021 10:04 AM)Guenter Schink Wrote:  Yes, an integer is required, be it decimal or hex. A little "lambda" may be of help to create it rather than calculate it by hand. E.g:

Code:

RGB=lambda red, green, blue: (((red*256)+green)*256)+blue
draw_filled_polygon([(0,0),(160,120),(0,240)],RGB(120,120,120))

gets you a grey triangle

Günter

I'm a Python beginner. Can you tell me why use lambda over the following? What's the advantage?

Code:

def RGB(red,green,blue):
  return (((red*256)+green)*256)+blue

I'm a Python beginner too

Both are equivalent. Once something can be done in a one liner I'm tempted to do this.
In principle, as a beginner, I try to use some language specifics where I see them fit.
Here is some discussion on this subject. In short: you don't need it, but it may serve you well once you're accustomed to it.

Usually you would use <lambda> as an anonymous function directly:

Code:

draw_filled_polygon([(0,0),(160,120),(0,240)],(lambda red, green, blue: (((red*256) +green) *256) +blue)(120,120,100))

the arguments of the lambda function can of course be variables


Günter