About HP Prime factorization

11022020, 05:40 PM
Post: #3




RE: About HP Prime factorization
[quote='parisse' pid='138432' dateline='1604303926']
factor factors over the field of coefficients of the arguments. If you want to extend this field, you must give a 2nd argument specifying the extension. For example Code: P:=a*s^2+b*s+c; Thank you very much, never would have guessed that, but it makes sense. Now, just another question, let's say I want to factor the expression: a^2 2*a*b+b^2+s^2, it's easy to see that it is equivalent to: s^2 + (ab)^2. I know I can get to the second expression in the HP Prime by applying the factor function like this: factor(a^2 2*a*b+b^2)+s^2, but the point if it is possible for it to be done automatically with a function. This is particularly useful, for example, to getting the simplified expressions of typical laplace transforms with symbolic coefficients, such as the ones attached. 

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Messages In This Thread 
About HP Prime factorization  dah145  11022020, 06:28 AM
RE: About HP Prime factorization  parisse  11022020, 07:58 AM
RE: About HP Prime factorization  dah145  11022020 05:40 PM
RE: About HP Prime factorization  Albert Chan  11022020, 07:32 PM
RE: About HP Prime factorization  dah145  11032020, 03:46 AM
RE: About HP Prime factorization  dah145  11192020, 04:12 PM

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