Can you calculate Pi using a Solver?

[jthole]

(12-10-2019 07:45 PM)JurgenRo Wrote:  

(12-09-2019 03:35 PM)Valentin Albillo Wrote:  If your Solver has Square Root and Factorial, this one from Ramanujan converges very fast and it's quite simple, few bytes to program it and only a few terms to add up for full precision...



... and no trigs used, as requested, just basic arithmetic. Once you get 1/Pi just invert it with 1/x

Regards.
V.

(Pi^2)/6=sum_{n=1}^{infinity}1/n^2 might fall into the same category.
Juergen

Converges much more slowly though. I just let it run from n=0 to 1 million (on the 17Bii simulator on my iPhone), and the difference with the Pi constant is still -9,5x10E-7. In contrast, the one suggested by Valentin already equals the Pi constant for n=2.

I'll test it on the 17Bii later, to see how much slower than the iPhone 7 it is

Edit: in order not to pollute this thread, I posted the results here: https://www.hpmuseum.org/forum/thread-14101.html