Indefinite Integrals

[dalukner]

(12-09-2019 01:19 PM)Aries Wrote:  3*x^(4/3), I think you mean
The point here is, x^(1/3) is not the cubic root of x, that is true only for x>=0.
For x<0 the NthRoot function is not equivalent to ^(1/n).

Oops yeah that's what I meant. It was late at night. Is there another way to explain why the calculator does this? I don't fully understand. It makes more complex antiderivatives (and just about everything with fractional exponents) very messy.