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dynamical list problem
01-02-2019, 06:08 PM
Post: #2
RE: dynamical list problem
Your process is not clear.

(01-02-2019 04:36 PM)peacecalc Wrote:  4 {1 2 1 3} Now the first time for building an averge value: m = 4/3 + (3-2)/(1/3) = 13/3

I make the average \( \frac {1+2+1+3} 4 = \frac 7 4 \)

(01-02-2019 04:36 PM)peacecalc Wrote:  5 {1 2 1 3 2} m = 3/1 + 2/1 = 5.

Again, your process is not clear. How are you going from a list of 5 numbers to \( m=\frac 3 1 + \frac 2 1 = 5 \) ?

If you can explain in clearer terms exactly what you're trying to achieve, we might be able to help.
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Messages In This Thread
dynamical list problem - peacecalc - 01-02-2019, 04:36 PM
RE: dynamical list problem - grsbanks - 01-02-2019 06:08 PM
RE: dynamical list problem - BruceH - 01-02-2019, 06:47 PM
RE: dynamical list problem - peacecalc - 01-02-2019, 07:14 PM
RE: dynamical list problem - pier4r - 01-03-2019, 11:56 AM
RE: dynamical list problem - Albert Chan - 01-03-2019, 12:57 PM
RE: dynamical list problem - peacecalc - 01-03-2019, 02:11 PM
RE: dynamical list problem - Albert Chan - 01-03-2019, 03:13 PM
RE: dynamical list problem - peacecalc - 01-03-2019, 04:25 PM
RE: dynamical list problem - Thomas Klemm - 01-03-2019, 04:44 PM
RE: dynamical list problem - Albert Chan - 01-03-2019, 05:18 PM
RE: dynamical list problem - Thomas Klemm - 01-03-2019, 09:15 PM
RE: dynamical list problem - peacecalc - 01-04-2019, 08:51 AM
RE: dynamical list problem - BruceH - 01-04-2019, 01:21 PM
RE: dynamical list problem - Albert Chan - 01-04-2019, 02:34 PM
RE: dynamical list problem - Thomas Klemm - 01-04-2019, 11:57 AM
RE: dynamical list problem - peacecalc - 01-05-2019, 09:48 AM
RE: dynamical list problem - Thomas Klemm - 01-05-2019, 12:54 PM
RE: dynamical list problem - DavidM - 01-05-2019, 05:13 PM
RE: dynamical list problem - Thomas Klemm - 01-05-2019, 07:45 PM
RE: dynamical list problem - John Keith - 01-07-2019, 04:55 PM
RE: dynamical list problem - Thomas Klemm - 01-07-2019, 08:29 PM



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