Casio fx-29 - how to enter "y"

[Didier Lachieze]

(12-05-2018 08:53 AM)tcab Wrote:  I wonder what the relationship between ln and x^y is, such that the calculator feels the need to do this...

Once you have implemented the algorithms for ln(x) and e^x, you can easily get x^y as x^y = e^(ln(x)*y)