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little math problem October 2018
10-21-2018, 06:53 PM (This post was last modified: 10-21-2018 08:33 PM by Gene222.)
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RE: little math problem October 2018
(10-20-2018 09:35 PM)sasa Wrote:  If both rovers are "blind", i.e. cannot locate it's position and communicate with eventually orbital module when visible, the fastest and dynamic way I can think of is that both go to one of designated magnetic pole.

That way both will not miss each other, both will move cutting searching time on half, saving energy... In worst case scenario, both together will cross less than D to the designated pole, with in less than (D/V)/2. The best case scenario, of course, is when both are close to the designated pole, when both will cross less than D/2 in less than (D/V)/4 time.

This is a variation of sasa's solution, and would be unique to the Earth's moon. Program each rover to travel to the area on the moon, where the Earth is directly above the rover. If a rover has landed on the dark side of the moon, include a program where the rover would travel in a straight line along the plane of the sun and planets, until the Earth becomes in sight. Once the Earth is in sight, maneuver the rover until the Earth is directly above the rover. The worst case travel time would be where the rover travels (EDIT) about 3/4's the circumference of the moon.
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little math problem October 2018 - pier4r - 10-20-2018, 06:48 PM
RE: little math problem October 2018 - Gene222 - 10-21-2018 06:53 PM

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