Post Reply 
(12C) Solve f(x)=0 with modified Regula Falsi method
03-26-2018, 06:26 AM (This post was last modified: 03-26-2018 07:52 AM by Gamo.)
Post: #2
RE: (12C) Solve f(x)=0 with modified Regula Falsi method
I test this to find a root of a polynomial of this equation.

f(x)=X^4 - 4X^3 + 8X^2 + 20X - 65

Program Method:

ENTER
ENTER
ENTER
4
-
x
8
+
x
20
+
x
65
-

FIX 9
Initial Guess used: 0 ENTER 3 R/S > instant answer > 2.236067977

My favorite X^X=Y also work flawlessly.

For this equation somehow not working.

Solve X^3 = 3^X
Rewrite equation to X^3 - 3^X = 0

Program Method:

ENTER
ENTER
3
Y^X
X<>Y
3
X<>Y
Y^X
-

The answer is 2.478052679

I try initial guess 1 ENTER 3 R/S > return 3 press R/S again > Error 0

Did I do something wrong?

I try on the Newton's Method and work OK

Gamo
Find all posts by this user
Quote this message in a reply
Post Reply 


Messages In This Thread
RE: (12C) Solve f(x)=0 with modified Regula Falsi method - Gamo - 03-26-2018 06:26 AM



User(s) browsing this thread: 1 Guest(s)