quo, rem, quorem -> poly divide
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03-22-2018, 09:24 PM
(This post was last modified: 03-22-2018 09:27 PM by Han.)
Post: #8
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RE: quo, rem, quorem -> poly divide
First: Perhaps the partfrac() command may be helpful in what you are trying to achieve.
Quote:1. The division operator, with poly's as arguments, would, itself, need to be smart enough to know that since you are asking for a [quotient, remainder], the result would not be just any old "vector or list." Context sensitivity. Let's just say -- for the sake of academic discussion -- that the division operator could in fact discern through parsing parentheses that the numerator should return a [quotient, remainder] pair and not be treated as a vector or list. I.e. it behaves just how you imagined it should. How, then, would one quickly take this [quotient, remainder] pair and divide both components by a single polynomial (or ratio of polynomials) if one desired the output [quotient/(2x), remainder/(2x)] as a list/vector? Would we then have to apply some sort of quorem2list() command first? (If so, we're pretty much back to square one for a different set of users). My hunch is that / behaves the way it does for ratios of polynomials for the same reason that 13/7 stays exactly as 13/7. Graph 3D | QPI | SolveSys |
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Messages In This Thread |
quo, rem, quorem -> poly divide - DrD - 03-22-2018, 02:38 PM
RE: quo, rem, quorem -> poly divide - Han - 03-22-2018, 02:47 PM
RE: quo, rem, quorem -> poly divide - DrD - 03-22-2018, 04:31 PM
RE: quo, rem, quorem -> poly divide - Han - 03-22-2018, 06:00 PM
RE: quo, rem, quorem -> poly divide - Tim Wessman - 03-22-2018, 04:43 PM
RE: quo, rem, quorem -> poly divide - DrD - 03-22-2018, 04:57 PM
RE: quo, rem, quorem -> poly divide - DrD - 03-22-2018, 08:23 PM
RE: quo, rem, quorem -> poly divide - Han - 03-22-2018 09:24 PM
RE: quo, rem, quorem -> poly divide - DrD - 03-23-2018, 11:55 AM
RE: quo, rem, quorem -> poly divide - Han - 03-23-2018, 12:51 PM
RE: quo, rem, quorem -> poly divide - DrD - 03-23-2018, 01:21 PM
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