Small challenge

[Dieter]

(09-20-2017 07:54 PM)Pekis Wrote:  Thanks for your enlighting answer !
I had imagined only one solution:
M=amount to pay=6000
n=number of payments=24
i=number of the payment: i=1..n
Payement number i= 2/n*(1-i/(n+1)) * M
So it began with 480 and ended up with 20

I finally added this as a "special case".
Before I read Didier's and your reply. Really. ;-)

Dieter