Crash when Solve for Integral with 15C

[Dieter]

(09-02-2017 08:14 PM)rprosperi Wrote:  

(09-02-2017 06:42 PM)Gerson W. Barbosa Wrote:  ...
0 ENTER 216 ALPHA EE ALPHA XEQ ALPHA INTEG ALPHA => 1.7892E92 (5'17")
...

Ok, I just have to ask... why 216?

The integration limits have to be substituted, i.e. they are now 0³ = 0  and  6³ = 216.

Dieter