Oddity Using Root Finder with Integrator (long)

[Ben Fairbank]

Thank you for your comments, but I do not understand your reference to the "error." My post shows division, not multiplication, by the Beta function, no?
Since the only x-axis region of interest is that from 0 to 1, the only root of interest is the one that I found, .29. It is still not clear to me how to restrict the computational area of interest to the 0 to 1 interval.

Ben
Ben

(03-13-2014 07:15 AM)Werner Wrote:  Wolframalpha confirms the emulator's result:
(integrate (x^3*(1-x)^5) dx from x=0 to y)*beta(4,6)-0.25=0
y = -1.62561, and it's the only root.

UPDATE: and that shows the error you (and I) made...
If I change it to *divide* by beta(4,6):

(integrate (x^3*(1-x)^5) dx from x=0 to y)/beta(4,6)-0.25=0
There are three roots,
y = -0.17836
y = 0.290986
y = 1.3936