sqrt question

[pier4r]

literally asking google (I guess they do not have enough input checks).



After some more thinking, I guess google is quite right. I was fooled at first.

\( \sqrt{-4} \cdot \sqrt{-9} = \sqrt{4 i^2 } \cdot \sqrt{9 i^2 } = \sqrt{36 i^4 } = 6i^2 = -6 \)

refreshing the operators precedence: https://en.wikipedia.org/wiki/Order_of_operations . The root come firsts, so "6" is not possible (that is, taking away the minus sign because -1*-1 = 1 , if one does not consider it as iota squared).