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(sqrt(-2))^2
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10-07-2016, 06:27 AM
Post: #16
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RE: (sqrt(-2))^2
In fact, I now think that the best way to reflect the 2-d template (where the sqrt bar has a variable width) would be to translate √... to sqrt(...)
For √(-2)^2 I don't think there is a universal convention for the precedence between √ and ^, that explains the difference. |
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(sqrt(-2))^2 - retoa - 10-05-2016, 02:33 PM
RE: (sqrt(-2))^2 - toml_12953 - 10-05-2016, 03:01 PM
RE: (sqrt(-2))^2 - retoa - 10-05-2016, 03:04 PM
RE: (sqrt(-2))^2 - parisse - 10-05-2016, 07:13 PM
RE: (sqrt(-2))^2 - retoa - 10-05-2016, 09:24 PM
RE: (sqrt(-2))^2 - Tim Wessman - 10-05-2016, 10:37 PM
RE: (sqrt(-2))^2 - parisse - 10-06-2016, 05:10 AM
RE: (sqrt(-2))^2 - retoa - 10-06-2016, 06:47 AM
RE: (sqrt(-2))^2 - Tim Wessman - 10-06-2016, 02:12 PM
RE: (sqrt(-2))^2 - parisse - 10-06-2016, 06:05 PM
RE: (sqrt(-2))^2 - John P - 10-06-2016, 07:26 PM
RE: (sqrt(-2))^2 - compsystems - 10-06-2016, 07:58 PM
RE: (sqrt(-2))^2 - compsystems - 10-06-2016, 04:01 PM
RE: (sqrt(-2))^2 - parisse - 10-06-2016, 08:19 PM
RE: (sqrt(-2))^2 - compsystems - 10-06-2016, 08:36 PM
RE: (sqrt(-2))^2 - parisse - 10-07-2016 06:27 AM
RE: (sqrt(-2))^2 - compsystems - 10-08-2016, 03:38 AM
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