Definite integration yields a strange answer. (Solved)
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01-30-2019, 08:21 PM
Post: #18
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RE: Definite integration yields a strange answer. (Solved)
(11-14-2015 08:13 PM)parisse Wrote: You misunderstand the meaning of the complex mode setting (note that this is named i on the Prime CAS settings, complex on the Prime is the complex variable mode setting). If you keep complex mode unchecked, it does not mean you will stay in the real domain. For example, sqrt(-1) will return i if complex is unchecked. Checking complex just says to the CAS that factor and associated functions should behave like if coefficients were complex even if they are all reals. Why x^(1/3) is a complex number if x<0 ? q is odd … |
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