# Line slope calculator 2x-3y=-8

**Straight line given by points A[2; 4] and B[5; 6]**

## Calculation:

**Slope-intercept form of line:**y = 0.6667x+2.6667

**Canonical form of the line equation:**2x-3y+8 = 0

**Parametric form of the line equation:**

x = 3t+2

y = 2t+4 ; t ∈ R

**Slope:**m = 0.6667

**Slope angle of line: φ =**33°41'24″ = 0.588 rad

**X intercept:**x

_{0}= -4

**Y intercept:**y

_{0}= q = 2.6667

**Distance line from the origin:**d

_{0}= 2.2188

**The length of the segment AB: |AB| =**3.6056

**Vector: AB =**(3; 2)

**Normal vector: n =**(2; -3)

**Midpoint of the segment AB: M =**[3.5; 5]

**Perpendicular Bisector equation:**3x+2y-20.5 = 0

**Vector OA = (2; 4) ; |OA| = 4.4721**

**Vector OB = (5; 6) ; |OB| = 7.8102**

**Scalar product OA .OB = 34**

**Angle ∠ AOB = 13°14'26″ = 0.2311 rad**