HP17bII+ Programming t-distribution
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07-25-2015, 02:03 PM
Post: #12
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RE: HP17bII+ Programming t-distribution
(07-25-2015 11:29 AM)Don Shepherd Wrote: I think I am getting outside of my area of comfort! You might still remember Valentin's HP-15C Mini-challenge that was solved by Gerson using Euler's reflection formula: \(\Gamma(z)\Gamma(1-z) = \frac{\pi}{\sin{(\pi z)}}\) Now if you set \(z=\frac{1}{2}\) you get: \(\Gamma(\tfrac{1}{2})\Gamma(\tfrac{1}{2}) = \frac{\pi}{\sin{(\tfrac{\pi}{2})}} = \frac{\pi}{1} = \pi \) From this we can conclude that in fact: \(\Gamma(\tfrac{1}{2})=\sqrt{\pi}\) Often I have to write down concrete examples to understand formulas. Thus for \(\nu=6\) we can use \(\Gamma(x+1)=x \Gamma(x)\) to get: \(\begin{align} \Gamma(\frac{\nu+1}{2})&=\Gamma(\frac{7}{2})=\Gamma(\frac{5}{2}+1) \\ &=\frac{5}{2}\cdot\Gamma(\frac{5}{2}) \\ &=\frac{5}{2}\cdot\frac{3}{2}\cdot\Gamma(\frac{3}{2}) \\ &=\frac{5}{2}\cdot\frac{3}{2}\cdot\frac{1}{2}\cdot\Gamma(\frac{1}{2}) \\ &=\frac{5}{2}\cdot\frac{3}{2}\cdot\frac{1}{2}\cdot\sqrt{\pi} \\ \end{align}\) We don't end up with a factorial but with the double factorial 5!! in the numerator. Thus we just insert the missing values which happen to be even: \(\begin{align} \Gamma(\frac{7}{2})&=\frac{5}{2}\cdot\frac{3}{2}\cdot\frac{1}{2}\cdot\sqrt{\pi} \\ &=\frac{5}{2}\cdot\frac{4}{4}\cdot\frac{3}{2}\cdot\frac{2}{2}\cdot\frac{1}{2}\cdot\sqrt{\pi} \\ &=\frac{5}{2}\cdot\frac{4}{2\cdot2}\cdot\frac{3}{2}\cdot\frac{2}{2\cdot 1}\cdot\frac{1}{2}\cdot\sqrt{\pi} \\\end{align}\) Now we end up with 5! in the nominator. In the denominator we end up with the product of 25 and 2!: \(\Gamma(\frac{7}{2})=\frac{5!}{2^5\,2!}\,\sqrt{\pi}\) Compare this to the general formula if you set \(\nu=6\): \(\Gamma(\frac{6+1}{2})=\frac{(6-1)!}{2^{6-1}\,(\frac{6}{2}-1)!}\,\sqrt{\pi}\) Quote:Something in my implementation of that equation causes the 17b to not be able to evaluate it at all. I didn't enter your formula but as it's written right now the T=(…) is missing. I assume that in this case the expression is just set to 0. And this might explain that no solution was found. HTH Thomas |
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