HP 11C real root finder [Newton Method]

[Dieter]

(01-12-2014 08:31 AM)Namir Wrote:  ...h = 0.001*(ABS(X)+1)

First of all, instead of multiplying with \(10^{-3}\), dividing by \(10^{3}\) is one step shorter. ;-)

This method for determining h will work in most cases, but not for very small arguments. Consider \(x = 10^{-4}\) or even \(x = 10^{-40}\). That's why I prefer \(h = x/10^4\). On the 34s, the result can be easily rounded to 1 or 2 significant digits (RSD 1) to prevent slight roundoff errors. As usual, \(x=0\) is handled as \(x=1\).

Dieter