Calcuator forensics history question

[J-F Garnier]

(04-20-2021 07:48 AM)EdS2 Wrote:  It's unfortunate that we now have two different tests in this thread - one using reciprocal and the other using square root. So that makes it difficult to compare results.

All these variants are based on the same quirk. they look complicate but the bottleneck is the COS ACOS sequence with an argument less than 1 degree (since it comes from SIN)
If I remove the COS and ACOS terms, even my Novus Mathematician gives 28.99983, which is really good for this very limited machine.

Just do .5 COS ACOS on various old machines and see what happens (modern machines will have no problem of course).

J-F