Prime calculator sum(1.0002^n/n, 1, 20000)

[John Keith]

(12-27-2020 03:04 AM)Gil Wrote:  On the HP50G, I get the wished answer by writing
directly sum(1.0002^n/n, 1, 20000).

For the HP 50, the correct syntax is '\GS(n=1, 20000, 1.0002^n/n)' where \GS is the Sigma character (right-shift S).

On a physical HP 50g, I get 28.1439738407 in 354.6 seconds, or just under 6 min.