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Solving equations in a given range
03-24-2020, 07:00 PM
Post: #2
RE: Solving equations in a given range
That's because the default step for the bisection solver is too large to detect the roots. You can obtain more solutions by adding an optional argument, like this
solve(tan(3x)=-x^2+3,x=10..15,xstep=0.001)
or
solve(tan(3x)=-x^2+3,x=25..30,10000)
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RE: Solving equations in a given range - parisse - 03-24-2020 07:00 PM



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