overflow

[J-F Garnier]

(03-08-2020 01:07 PM)Joe Horn Wrote:  (1) Be sure you're in CAS view. This doesn't work in Home. Why? Dunno.
(2) log10(2018.)*2442 [Be sure to include the decimal point!] --> 8070.61747736
(3) alog10(fp(Ans)) --> 4.1445497719

... Therefore, the answer for 2018^2442 is 4.14455 × 10^8070.

(03-08-2020 02:52 PM)Albert Chan Wrote:  Another way, by scaling x^y to k (1+ε)^y

2018^2442
= 1.009^2442 * 4 * 2^2440 * 1000^2442
= 1.009^2442 * 4 * 1.024^244 * 1000^(2442+244)
≈ 4.144549796E12 * 10^8058
= 4.144549796 * 10^8070

Combining the simple method 1 and the more accurate method 2:
(1) 2018^2442 = 2.018^2442 * 10^(3*2442)
(2) log10(2.018)*2442--> 744.617477362
(3) alog10(fp(Ans)) --> 4.14454979627
(4) 3*2442+744=8070

Therefore, the answer for 2018^2442 is 4.144549796 × 10^8070.

J-F