Try to plot x^(2/3).. what happen for x<0 ?

[ijabbott]

You can redefine the second one as \( \big( \sqrt[3]{x}\big)^2 \) to square the real cube root of \( x\).

Note that \(x^\frac{1}{3}\) and \(\sqrt[3]{x}\) are treated differently, and that \(x^\frac{1}{3}\) usually produces a complex number when \( x < 0 \), and its square is also complex, so it cannot be plotted by the Function app.