riddle
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12-11-2018, 06:00 PM
(This post was last modified: 12-11-2018 09:22 PM by Albert Chan.)
Post: #6
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RE: riddle
223092870 = 2·3·5·7·11·13·17·19·23
This SS# had huge number of factors = 2^9 = 512 For valid SS# (i.e. 9 digits limits), what number have most factors ? Edit: these 9-digits numbers have maximum of 1344 factors http://math.univ-lyon1.fr/~nicolas/ramanujanNR.pdf, page 152 735134400 = 2^6 * 3^3 * 5^2 * 7 * 11 * 13 * 17 821620800 = 2^6 * 3^3 * 5^2 * 7 * 11 * 13 * 19 931170240 = 2^6 * 3^2 * 5 * 7 * 11 * 13 * 17 * 19 994593600 = 2^6 * 3^3 * 5^2 * 7 * 11 * 13 * 23 |
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Messages In This Thread |
riddle - Don Shepherd - 12-11-2018, 01:41 PM
RE: riddle - Joe Horn - 12-11-2018, 04:32 PM
RE: riddle - Don Shepherd - 12-11-2018, 05:08 PM
RE: riddle - Albert Chan - 12-11-2018, 05:28 PM
RE: riddle - Don Shepherd - 12-11-2018, 05:38 PM
RE: riddle - Joe Horn - 12-12-2018, 06:43 AM
RE: riddle - Albert Chan - 12-11-2018 06:00 PM
RE: riddle - Don Shepherd - 12-11-2018, 09:34 PM
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