What Secrets the Bisection Method Hides?
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05-31-2018, 11:40 PM
Post: #4
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RE: What Secrets the Bisection Method Hides?
(05-31-2018 07:25 PM)Claudio L. Wrote:(05-31-2018 12:48 PM)Namir Wrote: C = (w1 * A + w2 * B) / (w1 + w2) The paper shows different cases for w1+w2 (using manual selection): 1) Sum is under 2. I just chose to assign 1 to one weight and calculate teh other weight as sum - 1. I could have used different numbers. 2) Sum is equal to 2, but w1 <> 1 and w2 <> 1. 3) Sum > 2 and w1 and w2 are selected to enhance the advantageous root-bracketing end. Another approach is to use the absolute function values to calculate w1 and w2. So the paper shows two approaches. You have total freedom to select w1 and w2 as long as it obeys: C = (w1 * A + w2 * B) / (w1 + w2) The relative values of w1 and w2 that you select will influence convergence rate, which of course greatly depends on the f(x) and the tolerance value for the refined guess for the root. Namir |
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Messages In This Thread |
What Secrets the Bisection Method Hides? - Namir - 05-31-2018, 12:48 PM
RE: What Secrets the Bisection Method Hides? - Claudio L. - 05-31-2018, 07:25 PM
RE: What Secrets the Bisection Method Hides? - Namir - 05-31-2018 11:40 PM
RE: What Secrets the Bisection Method Hides? - Claudio L. - 06-01-2018, 06:38 PM
RE: What Secrets the Bisection Method Hides? - Namir - 06-03-2018, 12:15 PM
RE: What Secrets the Bisection Method Hides? - ttw - 05-31-2018, 08:35 PM
RE: What Secrets the Bisection Method Hides? - ttw - 06-01-2018, 08:57 AM
RE: What Secrets the Bisection Method Hides? - Namir - 06-01-2018, 04:51 PM
RE: What Secrets the Bisection Method Hides? - ttw - 06-05-2018, 12:56 AM
RE: What Secrets the Bisection Method Hides? - Namir - 06-05-2018, 05:30 AM
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