How to evaluate A Taylor series at a specific value

08232018, 02:30 PM
Post: #24




RE: How to evaluate A Taylor series at a specific value
(08222018 07:52 PM)parisse Wrote:  is evaluated more like a program, where x would be like an argument. If "" is like running a program with argument x: taylor(sin(x))x=0.5 ==> (lambda x: taylor(sin(x))) (0.5) ==> taylor(sin(0.5)) ==> sin(0.5) sin(x)x=2 ==> (lambda x: sin(x))(2) ==> sin(2) Why does "" hard to evaluate ? Why previous run of x := 1 affect it ? Maybe "" is simply "evaluate at" ? However, that imply taylor had a bug (post #23) 

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