(12C) Hyperfocal Distance

[Dieter]

(05-02-2018 10:27 AM)Mike (Stgt) Wrote:  

(05-02-2018 06:31 AM)Dieter Wrote:  You can derive the formula yourself: with g being the object distance and b being the image distance, b = g²/(g–f). This follows from the basic relation 1/b+1/g = 1/f. My formula calculates g+b. So simply substitute g with f²/Ac+f and there you are.

Got it. Thank you.

Fine. You obviously could do it without the given b formula, because ...it was wrong.
Of course it should have read...

b = gf/(g–f)
- or -
b+g = g²/(g–f)

I corrected the previous post accordingly.

Dieter