Differential Equation Entry?

04102018, 11:14 AM
Post: #1




Differential Equation Entry?
How can this be solved using the prime: (Ideally, returning BOTH a general and a particular solution.)
(y*e^x) dx + (y^2  1) dy = 0, AND y(0) = 1 Desired results: y^2  ln(y^2) = 2*e^x + c1; {General Solution} y^2  ln(y^2) = 2*e^x + 3; {Particular solution} 

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Differential Equation Entry?  DrD  04102018 11:14 AM
RE: Differential Equation Entry?  parisse  04102018, 11:53 AM
RE: Differential Equation Entry?  DrD  04102018, 01:22 PM

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