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(Free42) roundoff for complex SQRT
04-03-2018, 01:48 PM
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Thomas Okken Offline
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RE: (Free42) roundoff for complex SQRT
Yup, there's no special case for pure imaginary in SQRT. It looks like this fell between the cracks when I did the grand cleanup of pure-real and pure-imaginary complex transcendentals last year. Because SQRT is not a transcendental function, I guess. Smile
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RE: (Free42) roundoff for complex SQRT - Thomas Okken - 04-03-2018 01:48 PM



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