(Free42) roundoff for complex SQRT

02122021, 02:45 PM
Post: #21




RE: (Free42) roundoff for complex SQRT
Resurrecting this old thread ...
When X = 0+iB, SQRT(X) should have equal real and imaginary parts (apart from the sign). But that is (still) not the case. The 48G algorithm I posted gives the correct result  in the 48, with its 3 extra digits, but not in Free42. Example: 1E12 SQRT SQRT COMPLEX  equals 1E37, exactly what you get when you follow the 48G algorithm. Cheers, Werner 

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