(12C) Solve f(x)=0 with modified Regula Falsi method
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03-26-2018, 06:26 AM
(This post was last modified: 03-26-2018 07:52 AM by Gamo.)
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RE: (12C) Solve f(x)=0 with modified Regula Falsi method
I test this to find a root of a polynomial of this equation.
f(x)=X^4 - 4X^3 + 8X^2 + 20X - 65 Program Method: ENTER ENTER ENTER 4 - x 8 + x 20 + x 65 - FIX 9 Initial Guess used: 0 ENTER 3 R/S > instant answer > 2.236067977 My favorite X^X=Y also work flawlessly. For this equation somehow not working. Solve X^3 = 3^X Rewrite equation to X^3 - 3^X = 0 Program Method: ENTER ENTER 3 Y^X X<>Y 3 X<>Y Y^X - The answer is 2.478052679 I try initial guess 1 ENTER 3 R/S > return 3 press R/S again > Error 0 Did I do something wrong? I try on the Newton's Method and work OK Gamo |
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Messages In This Thread |
(12C) Solve f(x)=0 with modified Regula Falsi method - Dieter - 03-25-2018, 05:58 PM
RE: (12C) Solve f(x)=0 with modified Regula Falsi method - Gamo - 03-26-2018 06:26 AM
RE: (12C) Solve f(x)=0 with modified Regula Falsi method - Dieter - 03-26-2018, 07:43 AM
RE: (12C) Solve f(x)=0 with modified Regula Falsi method - Gamo - 03-26-2018, 01:04 PM
RE: (12C) Solve f(x)=0 with modified Regula Falsi method - Dieter - 03-26-2018, 04:37 PM
RE: (12C) Solve f(x)=0 with modified Regula Falsi method - Dieter - 03-27-2018, 06:13 PM
RE: (12C) Solve f(x)=0 with modified Regula Falsi method - Carsen - 03-26-2018, 10:24 PM
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