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+--- Thread: antilog on 12C (/thread-8855.html)
antilog on 12C - Zac Bruce - 08-17-2017 09:18 AM
Evening all,
I'm hoping someone more mathematically minded than me can tell me how I can calculate the common antilog on a HP 12c, if it is indeed possible.
I'm making an attempt to teach myself (pre-calculus) mathematics, with the aid of a self paced course at my university and Schaums Outline. I know that the common logarithm can be calculated by e.g. 'x'LN 10LN /
but my feeble powers of math doesn't let me see the solution using the natural antilog in a similar way, if this is possible.
Thanks in advance,
Zac
RE: antilog on 12C - Dieter - 08-17-2017 11:33 AM
(08-17-2017 09:18 AM)Zac Bruce Wrote: Evening all,
It's lunch break over here. ;-)
(08-17-2017 09:18 AM)Zac Bruce Wrote: I'm hoping someone more mathematically minded than me can tell me how I can calculate the common antilog on a HP 12c, if it is indeed possible.
The common antilog is 10x. So simply type 10 [x<>y] [yx].
Or if you prefer a somewhat more complicated method: 10 [ln] [x] [ex].
The latter may cause slight roundoff errors, e.g. x=5 returns 100 000,0005 instead of exactly 100 000.
(08-17-2017 09:18 AM)Zac Bruce Wrote: I know that the common logarithm can be calculated by e.g. 'x'LN 10LN /
but my feeble powers of math doesn't let me see the solution using the natural antilog in a similar way, if this is possible.
The natural antilog is ex. The 12C has a key for that. ;-)
Dieter
RE: antilog on 12C - Zac Bruce - 08-17-2017 10:51 PM
(08-17-2017 11:33 AM)Dieter Wrote:(08-17-2017 09:18 AM)Zac Bruce Wrote: Evening all,
It's lunch break over here. ;-)
The common antilog is 10x. So simply type 10 [x<>y] [yx].
The natural antilog is ex. The 12C has a key for that. ;-)
Dieter
Thanks Dieter,
This was exactly what I was looking for. As I've said before; everything is easy, when you know how. It's a shame it wasn't included in the manual, the solutions handbook or in the "logarithm and exponential" training module. I was aware of the natural log/antilog. I believe we may have had a discussion involving those when I was trying to work out how to solve for 'n' in compound interest problems.
I recently picked up a 35s secondhand quite cheap, and so it was actually nice to have a reason to pick that up and play around with it while my mathematically crippled brain was trying to work out what is actually going on with logarithms/anitlogs.
Thanks again,
Zac