 CAS.numer; denom; lcoeff; degree... ??!! [It's OK NOW ! :o)] - Printable Version +- HP Forums (https://www.hpmuseum.org/forum) +-- Forum: HP Calculators (and very old HP Computers) (/forum-3.html) +--- Forum: HP Prime (/forum-5.html) +--- Thread: CAS.numer; denom; lcoeff; degree... ??!! [It's OK NOW ! :o)] (/thread-3090.html) CAS.numer; denom; lcoeff; degree... ??!! [It's OK NOW ! :o)] - dg1969 - 02-14-2015 07:35 PM I can't find a way to use lcoeff; degree; coeff in a home program... Code:  CAS.numer("(2+x^2)/(1+x)") is ok => x^2+2 CAS.denom("(2+x^2)/(1+x)") is ok => x+1 but : CAS.coeff("x^2+2,2") =>0 CAS.lcoeff("3*x^3+2*x") => 3*x^2+2 in place of 3 CAS.degree("3*x^3+2*x") => 0 !! CAS.froot("(1+x^2)/(1-x)") =>[] !! In my mind string inside CAS.cas_stuff("...") is the good practice ? these code doesn't work... Code:  f:="numer((1+x^2)/(1+x))"; num:=CAS(f); RE: CAS.numer; denom; lcoeff; degree... ??!! - dg1969 - 02-14-2015 08:34 PM I need these functions in a home program because i'd like to compute symbolicaly the phase $$\varphi$$ of a transfer functions $$\dfrac{P(s)}{Q(s)}\cdot e^{-k\cdot s}$$ initially placed in F0 to F9 var in term of 'X' in a FUNCTION APP like "froot" from CAS give me all roots of numerator and denom with multiplicity so : $$F(s)=K\cdot\dfrac{(s-r1)...(s-r_n)}{(s-p_1)...(s-p_m)}\cdot e^{-k\cdot s}$$ with $$n \leq m$$ $$\varphi=arg(F(i\cdot \omega)$$ lcoeff(numer)/lcoeff(denom) give me $$K$$ so first term of $$\varphi$$ is known I can easily compute the major terms of the sum of $$\varphi$$ : $$+/-m_i\cdot atan \dfrac{\beta_i-\omega}{\alpha_i}$$ where $$\omega$$ is the pulsation ; $$\alpha_i; \beta_i ;m_i$$ are resp the real part the imaginary part and multiplicity of roots and poles of $$F(s)$$ I need to test if an exp term is there to add the last term in the phase sum... Don't know how to parse yet... At the end I want to place these phase functions in F_i var's in term of 'X' for plot... I try these way to plot bode phase without +/- pi discontinuity... At the end I want to keep benefits of the function app plot facility (max, zero etc...) RE: CAS.numer; denom; lcoeff; degree... ??!! - Han - 02-16-2015 07:53 PM (02-14-2015 07:35 PM)dg1969 Wrote:  I can't find a way to use lcoeff; degree; coeff in a home program... Code:  CAS.numer("(2+x^2)/(1+x)") is ok => x^2+2 CAS.denom("(2+x^2)/(1+x)") is ok => x+1 but : CAS.coeff("x^2+2,2") =>0 CAS.lcoeff("3*x^3+2*x") => 3*x^2+2 in place of 3 CAS.degree("3*x^3+2*x") => 0 !! CAS.froot("(1+x^2)/(1-x)") =>[] !! In my mind string inside CAS.cas_stuff("...") is the good practice ? these code doesn't work... Code:  f:="numer((1+x^2)/(1+x))"; num:=CAS(f); Tried with the emulator, and everything works properly here for me. As for CAS.coeff("x^2+2,2") =>0 are you sure you didn't mean CAS.coeff("x^2+2","2") Notice the quotes around each argument (the second set of quotes is unnecessary since the 2 is not symbolic) RE: CAS.numer; denom; lcoeff; degree... ??!! [IT'S OK NOW !] - dg1969 - 02-16-2015 08:45 PM Han. You are absolutely irreplaceable ! Thank you for your endless patience. I just found something you already knew. Integrated help does not give the exact syntax for the HOME side which is in fact different from the CAS side. In CAS side: Code:  froot((1+x^3)/(1+2*x)) is ok not need the second argument: 'x' but it is essential in the "home" side. The aid does not indicate expect for : Code:  CAS.coeff("x^2+3-2*x","x","2") (I am the only guilty 3 args clearly mentioned in the help) so Code:  CAS.froot("(1+x^2)/(2*x+x^3)","x") or with a single string : Code:  CAS.froot("(1+x^2)/(2*x+x^3),x") working perfectly ! It's the same thing for other commands that I mentioned... Han, you know what ? You are my best cyber-friend :o)