Integration by substitution: how to ? - Printable Version +- HP Forums ( https://www.hpmuseum.org/forum)+-- Forum: HP Calculators (and very old HP Computers) ( /forum-3.html)+--- Forum: HP Prime ( /forum-5.html)+--- Thread: Integration by substitution: how to ? ( /thread-2265.html) |

Integration by substitution: how to ? - Aries - 10-10-2014 10:47 AM
A very simple example can be the following: INT(1/(x+SQRT(x)))*dx. Changing variable u=SQRT(x) --> u^2=x (with u>=0) --> 1/(u^2+u) and dx=2u*dt. The integral now becomes INT(2u/(u^2+u))*du = INT(2/(u+1))*du = 2*ln |u+1|+c (that is 2*ln |SQRT(x)+1|+c). How could I do with the Prime ? TIA, Aries RE: Integration by substitution: how to ? - parisse - 10-10-2014 01:37 PM
assume(u>0); a:=subst('integrate(1/(x+sqrt(x)),x)',x=u^2); a; RE: Integration by substitution: how to ? - Aries - 10-11-2014 08:16 AM
Thanks Mr Parisse, much appreciated ;-) |