# Line slope calculator x+4y=16

**Straight line given by points A[0; 4] and B[4; 3]**

## Calculation:

**Slope-intercept form of line:**y = -0.25x+4

**Canonical form of the line equation:**x+4y-16 = 0

**Parametric form of the line equation:**

x = 4t

y = -t+4 ; t ∈ R

**Slope:**m = -0.25

**Slope angle of line: φ =**-14°2'10″ = -0.245 rad

**X intercept:**x

_{0}= 16

**Y intercept:**y

_{0}= q = 4

**Distance line from the origin:**d

_{0}= 3.8806

**The length of the segment AB: |AB| =**4.1231

**Vector: AB =**(4; -1)

**Normal vector: n =**(1; 4)

**Midpoint of the segment AB: M =**[2; 3.5]

**Perpendicular Bisector equation:**4x-y-4.5 = 0

**Vector OA = (0; 4) ; |OA| = 4**

**Vector OB = (4; 3) ; |OB| = 5**

**Scalar product OA .OB = 12**

**Angle ∠ AOB = 53°7'48″ = 0.9273 rad**