wp34s minichallenge

09232020, 12:59 AM
Post: #1




wp34s minichallenge
√(5 + (ϕ^2 + 1)  (5×10^5)/((ϕ^2 + 1) + 10^5))
Evaluate the above expression on the wp34s striving to use the least number of steps. You might need to rewrite it in order to do it in less than 12 steps. Notice ϕ is a builtin constant. Have fun! 

09232020, 09:14 PM
(This post was last modified: 09232020 09:26 PM by Namir.)
Post: #2




RE: wp34s minichallenge
My 11 step solution is 41ish.
Let a = phi^2 + 1 let b = 10^5 The expression is sqrt(5 + a  5b/(a + b)) ... upon simplification we get: sqrt(5a/(a+b) + a) The pseudocode is based on the last equation. Code: Phi 

09232020, 11:41 PM
(This post was last modified: 09232020 11:51 PM by Gerson W. Barbosa.)
Post: #3




RE: wp34s minichallenge
(09232020 09:14 PM)Namir Wrote: My 11 step solution is 41ish. Namir, thank you very much for your interest! Unfortunately, however, EEX 5 requires two steps on the wp34s. Also, your solution doesn’t return the expected result unless I’m mistaken. Tip: ϕ^2 + 1 = ϕ + 2 

09242020, 03:05 AM
Post: #4




RE: wp34s minichallenge
(09232020 11:41 PM)Gerson W. Barbosa Wrote:(09232020 09:14 PM)Namir Wrote: My 11 step solution is 41ish. :( 

09242020, 10:31 AM
Post: #5




RE: wp34s minichallenge
Here is a 12step solution using your simplification:
001:# Φ 002:x² 003:INC X 004:RCL X 005:# 005 006:× 007:RCL L 008:10ᵡ 009:RCL+ Z 010:/ 011:+ 012:√ 

09242020, 07:49 PM
Post: #6




RE: wp34s minichallenge
Here is the corrected version based on your comments and hint:
Code: Phi 

09242020, 08:00 PM
Post: #7




RE: wp34s minichallenge  
09242020, 08:18 PM
Post: #8




RE: wp34s minichallenge
Here is the corrected version based on your comments and hint:
Code: Phi 

09242020, 09:17 PM
(This post was last modified: 09242020 09:18 PM by Gerson W. Barbosa.)
Post: #9




RE: wp34s minichallenge
(09242020 08:00 PM)Didier Lachieze Wrote:(09242020 10:31 AM)Gerson W. Barbosa Wrote: Here is a 12step solution using your simplification: And using ordinary wp34s instructions only. Formidable ! I had to rewrite the original expression and to resort to a somewhat obscure instruction: √(7 + ϕ  5/(1 + (ϕ + 2)/10^5)) 001:# 007 002:# ϕ 003:+ 004:# 005 005:# 002 006:RCL+ L 007:Pa→bar 008:INC X 009:/ 010: 011:√ → 1.9021605831 That’s an approximation to a mathematical constant which is know to only nine significant digits, according to OEIS. Anyway, it agrees to Pascal Sebah’s result to 12 significant digits. 

09242020, 09:29 PM
Post: #10




RE: wp34s minichallenge
(09242020 08:18 PM)Namir Wrote: Here is the corrected version based on your comments and hint: It looks like my hint was somewhat misleading, as your simplification does allow for an 11step solution (see Didier’s solution above). Sorry! Your fourth step should be replaced with FILL (fill up the stack with a constant) as you need an extra copy of Phi on the stack. 

09272020, 07:07 PM
Post: #11




RE: wp34s minichallenge
It can be done in 10 steps. Any takers?


10022020, 02:47 PM
Post: #12




RE: wp34s minichallenge
(09272020 07:07 PM)Gerson W. Barbosa Wrote: It can be done in 10 steps. Any takers? Ok, then I'll take it! (See solution #2, solution #1 and some variations thereof is what I already had). 1) √{5[5(ϕ + 2)/10^5] + ϕ + 2} [ ab = ab/(a + b) ] 001:# ϕ 002:# 002 003:+ 004:# 005 005:SDR 005 006:RCL× Y 007:# 005 008: 009:+ 010:√ → 1.902160583101354 2) √{ϕ + 2 + [0.2 + 20000/(ϕ + 2)]⁻¹} 001:# 002 002:SDR 001 003:# ϕ 004:RCL+ L 005:# 200 006:%T 007:RCL+ Z 008:1/x 009:+ 010:√ 

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