Int (ln(tan(X)))/((sin(X))(cos(X))) returns the integral
TI NSpire returns ((ln(tan(X)))^2)/2
Both return same answer in approximate mode.
...that is, when made into a definite integral!
(08-21-2016 10:14 PM)lrdheat Wrote: [ -> ]Int (ln(tan(X)))/((sin(X))(cos(X))) returns the integral
TI NSpire returns ((ln(tan(X)))^2)/2
Both return same answer in approximate mode.
Are you sure the parentheses in your input are correct? As shown, the integral ends before the division sign, which I suspect is not what you wanted.
If you derive (ln(tan(x)))^2, there should be a (1+tan(x)^2) term, but I don't see it in your input (which has strange parenthesis and missing * sign).
Hello Bernard.
Using 1+tan^2 = 1/cos^2,
the derivative of ((ln(tan(x))^2)/2 is ln(tan(x))/(sin(x)*cos(x)),
which is what I think the original poster meant.
I have no Prime to verify though.
Cheers, Werner
(08-21-2016 10:14 PM)lrdheat Wrote: [ -> ]Int (ln(tan(X)))/((sin(X))(cos(X))) returns the integral
TI NSpire returns ((ln(tan(X)))^2)/2
Both return same answer in approximate mode.
* is missing and parenthesis levels are "untidy" ;-)
Best,
Aries :-)
Hi!
This is what I get (with 10077).
Irdheat is OK.
Marcel.
Xcas also behaves the same. Thanks!
Then you can solve it with trigtan
a:=int(ln(tan(x))/(sin(x)*cos(x))); trigtan(a)
Don't know if this is related or not but ∫(ln(tan(x)),x) returns the following screen shot:
[
attachment=3848]
the denominator is +([TAN(x)^2 1]). The plus sign is located incorrectly but when you copy it onto the command line it is correct.
This is with 10077.
-road
This is unrelated, but thanks for the bug report!