07-31-2016, 04:10 AM
Sorry for my bad English
Source https://www-fourier.ujf-grenoble.fr/~par...el001.html
HPPrimeCAS (CAS March 14 2016)
xCAS (xcas 1.2.2-75)
Installer xcasunst.exe
https://www-fourier.ujf-grenoble.fr/~par...asunst.exe
Example 1:
1/3+1/4 [enter]
CAS: Simplify: None
returns 7/2
xCAS: Autosimplify: nop
returns 7/2
2:
(sqrt(2))^5 [enter]
CAS: Simplify: None
returns √(2)*2^2
xCAS: Autosimplify: nop
returns sqrt(2)*2^2
Same in both cases
2.1:
(sqrt(2))^5 [enter]
CAS: Simplify: Minimum
returns √(2)*4
xCAS: Autosimplify: regroup
returns sqrt(2)*4
3: solve(a*x^2+b*x+c,x)
CAS: Simplify: None
returns
Warning, argument is not an equation, solving a*x^2+b*x+c=0
{((1/2)*(-b+√(-4*a*c+b^2))/a),((1/2)*(-b-√(-4*a*c+b^2))/a)}
xCAS: Autosimplify: nop
returns
Warning, argument is not an equation, solving a*x^2+b*x+c=0
list[(sqrt(-4*a*c+b^2)-b)/(2*a),(-(sqrt(-4*a*c+b^2))-b)/(2*a)]
the none/nop simplification does not work, Why?
3.1 solve(a*x^2+b*x+c=0,x)
CAS: Simplify: Maximum
returns
{ ((-b+√(-4*a*c+b^2))/(2*a)), ((-b-√(-4*a*c+b^2))/(2*a))}
Source https://www-fourier.ujf-grenoble.fr/~par...el001.html
HPPrimeCAS (CAS March 14 2016)
xCAS (xcas 1.2.2-75)
Installer xcasunst.exe
https://www-fourier.ujf-grenoble.fr/~par...asunst.exe
Example 1:
1/3+1/4 [enter]
CAS: Simplify: None
returns 7/2
xCAS: Autosimplify: nop
returns 7/2
2:
(sqrt(2))^5 [enter]
CAS: Simplify: None
returns √(2)*2^2
xCAS: Autosimplify: nop
returns sqrt(2)*2^2
Same in both cases
2.1:
(sqrt(2))^5 [enter]
CAS: Simplify: Minimum
returns √(2)*4
xCAS: Autosimplify: regroup
returns sqrt(2)*4
3: solve(a*x^2+b*x+c,x)
CAS: Simplify: None
returns
Warning, argument is not an equation, solving a*x^2+b*x+c=0
{((1/2)*(-b+√(-4*a*c+b^2))/a),((1/2)*(-b-√(-4*a*c+b^2))/a)}
xCAS: Autosimplify: nop
returns
Warning, argument is not an equation, solving a*x^2+b*x+c=0
list[(sqrt(-4*a*c+b^2)-b)/(2*a),(-(sqrt(-4*a*c+b^2))-b)/(2*a)]
the none/nop simplification does not work, Why?
3.1 solve(a*x^2+b*x+c=0,x)
CAS: Simplify: Maximum
returns
{ ((-b+√(-4*a*c+b^2))/(2*a)), ((-b-√(-4*a*c+b^2))/(2*a))}