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Looking for ideas:

I need to row sort M1, an (n x 4) matrix, in decreasing order of column 4. Then on decreasing order of column 2, if sorted M1 contains more than one row with equal column 4 values.

How can this be done?

Thanks,

-Dale-
This is bulky, but seems to work (better ideas?):

Code:
``` EXPORT sm(N) BEGIN      M1:=CAS("randMat(N,3,ip(1..10))");     //  Generate random M1(N,3) cut list: M1[#pieces,length,width] of N patterns    for I from 1 to length(M1) do               M1(I,4):=M1(I,2)*M1(I,3);            //  Create column 4, M1[#pieces,length,width,area]      end;   for I from 1 to length(M1) do     for J from I+1 to length(M1) do       IF M1(I,4)<M1(J,4) then SWAPROW(M1,J,I); end;  //  Sort column 4 in decreasing order     end;  // J   end;  // I   for I from 1 to length(M1)-1 do     for J from I+1 to length(M1) do       IF (M1(I,4)==M1(J,4)) AND (M1(I,2)<M1(J,2)) then SWAPROW(M1,I,J); end;  // Then sort column 2 decreasing, if equal col 4 values     end; // j   end;  // I    END;```

tnx,

-Dale-
Create a sort function, something like
f:=(x,y)->if y[4]!=x[4] then return x[4]>y[4] else return x[2]>y[2] end;
then sort(m,f) will sort a matrix m using f as a sort function.
Thank you for your very helpful suggestion! I like compact solutions like this, and I'll add it to my "how to" list for future reference.

-Dale-
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